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Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DMedium2 minQB

PhysicsMediumsingle choice

Two particles, one with constant velocity 50 m/s and the other with uniform acceleration 10 $m / s^{2}$ , start moving simultaneously from the same place in the same direction. They will be at a distance of 125 m from each other after:

Options:

Answer:

Solution:

$50 t - \frac{1}{2} (10) t^{2} = 125$ gives $t^{2} - 10 t + 25 = 0$ , so $t = 5$ s. Option A.

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: QB

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