Physics - Kinematics Question with Solution | TestHub

Let the initial velocity be $V_1=20m/s$ North and final velocity be $V_2=20m/s$ East.

The change in velocity is $\Delta V=V_2-V_1$.

Magnitude: $|\Delta V|=\sqrt{V_2^2+(-V_1{)}^2}=\sqrt{20^2+(-20{)}^2}=20\sqrt{2}m/s$.

Direction: South-East, as it's the vector sum of $V_2$ (East) and $-V_1$ (South).