A particle is projected upwards with a velocity of 110 m/s at an angle of 6 0 ∘ with the vertical. Find the time when the particle will move perpendicular to its initial direction, taking g = 10 m / s

Question

A particle is projected upwards with a velocity of 110 m/s at an angle of 6 0 ∘ with the vertical. Find the time when the particle will move perpendicular to its initial direction, taking g = 10 m / s 2 :

TestHub · Accepted Answer

The projection is 3 0 ∘ above the horizontal; the velocity is perpendicular to the initial direction when it points 6 0 ∘ below the horizontal: 110 cos 3 0 ∘ 110 sin 3 0 ∘ − 10 t ​ = − tan 6 0 ∘ , so 55 − 10 t = − 165 , t = 22 s. Option B.

Physics - Kinematics Question with Solution | TestHub

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