For the velocity-time graph shown in the figure, the total distance covered by the particle in the last two seconds of its motion is what fraction of the total distance covered by it in all the seven seconds?

Question

TestHub · Accepted Answer

Area under the v - t graph gives distance. From 1 s to 7 s: s = 2 1 ​ ( 3 − 1 ) ( 20 ) + ( 6 − 3 ) ( 20 ) + 2 1 ​ ( 7 − 6 ) ( 20 ) = 20 + 60 + 10 = 90 m. From 5 s to 7 s: s 2 ​ = ( 6 − 5 ) ( 20 ) + 2 1 ​ ( 1 ) ( 20 ) = 30 m. Fraction = 90 30 ​ = 3 1 ​ . Option D.

Physics - Kinematics Question with Solution | TestHub

Options:

Doubts & Discussion