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Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DMedium2 minQB

PhysicsMediumsingle choice

The velocity of a particle is $10 m / s$ for the first $1$ s, rises uniformly to $20 m / s$ at $t = 2$ s, stays $20 m / s$ until $t = 3$ s and falls uniformly to $10 m / s$ at $t = 4$ s. The distance covered in $4$ seconds is:

Options:

Answer:

Solution:

Areas: $(1) (10) = 10$ , $\frac{1}{2} (10 + 20) (1) = 15$ , $(1) (20) = 20$ , $\frac{1}{2} (20 + 10) (1) = 15$ ; total = $10 + 15 + 20 + 15 = 60$ m. Option C.

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: QB

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