Physics - Kinematics Question with Solution | TestHub

PhysicsKinematicsRelativeMedium2 minQB

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Two particles are projected from the two towers simultaneously as shown in the figure. If they collide, the time at which they collide is :-

Answer:

Solution:

Relative velocity along vertical: $u_{re l} = 102 cos 4 5^{\circ} - 0 = 10 m/s$ .

Relative acceleration: $a_{re l} = g - g = 0$ . Vertical separation $s_{re l} = 10 m$ .

$t = \frac{s _{re l}}{u _{re l}} = \frac{10}{10} = 1 s$ . Hence (D).

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:Relative

⏱ 2mℹ️ Source: QB

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