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Physics - Kinematics Question with Solution | TestHub

PhysicsKinematicsMiscellaneousHard2 minQB

PhysicsHardsingle choice

Passage / Comprehension

A projectile is observed moving with velocity m/s after 5 s of its projection from the ground. On the basis of the above information, find the following.

The maximum height attained by the projectile is

Options:

Answer:

Solution:

By using $v = u + at$

$30 i - 10 j = u + (- 10 j) (5) \Rightarrow u = (30 \hat{i} + 40 \hat{j}) m / s$

Time of flight $T = \frac{2 u _{y}}{g} = \frac{2 ( 40 )}{10} = 8$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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