Displacement of particle in time interval 0 ≤ t ≤ 4 s is :-

Displacement of particle in 0 ≤ t ≤ 4 s = Displacement of balloon in first 4 seconds = ut + 2 1 at 2 = 0 + 2 1 ( 10 ) ( 4 ) 2 = 80 m

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Passage / Comprehension

A balloon rises up with constant acceleration of 10 m/s² from the Earth's surface at t=0.

After 4 seconds, a particle drops from the balloon.

Displacement of particle in time interval $0 \leq t \leq 4 s$ is :-

Answer:

Solution:

Displacement of particle in $0 \leq t \leq 4 s =$ Displacement of balloon in first 4 seconds

$= ut + \frac{1}{2} at^{2} = 0 + \frac{1}{2} (10) (4)^{2} = 80 m$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: QB

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