Two particles, one with constant velocity 40 m/s and the other with uniform acceleration 10 m / s 2 starting from rest, start moving simultaneously from the same place in the same direction. They will

Question

Two particles, one with constant velocity 40 m/s and the other with uniform acceleration 10 $m / s^{2}$ starting from rest, start moving simultaneously from the same place in the same direction. They will be at a distance of 80 m from each other after:

Options:

Answer:

B

Solution:

$40 t - 5 t^{2} = 80$ gives $t^{2} - 8 t + 16 = 0$ , so $t = 4$ s. Option B.

TestHub · Accepted Answer

40 t − 5 t 2 = 80 gives t 2 − 8 t + 16 = 0 , so t = 4 s. Option B.

Physics - Kinematics Question with Solution | TestHub

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