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Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DMedium2 minQB

PhysicsMediumsingle choice

The velocity of a particle moving on the $x$ -axis is given by $v = x^{2} + x$ , where $v$ is in m/s and $x$ in m. Its acceleration when passing through the point $x = 2$ m is:

Options:

Answer:

Solution:

$a = v \frac{d v}{d x} = (x^{2} + x) (2 x + 1)$ . At $x = 2$ : $a = (4 + 2) (4 + 1) = 6 \times 5 = 30 m / s^{2}$ . Option D.

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: QB

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