Physics - Kinematics Question with Solution | TestHub

$y=0$ at $x=0$ and $x=2$, so range = $2$ m; vertex $y(1)=1$ m; $\text{tan}\theta =2$; $u^2=\frac{g}{2{\text{cos}}^2\theta }=25$ with $\text{cos}\theta =1/\sqrt{5}$, so $T=\frac{2\times 5\times (2/\sqrt{5})}{10}=\frac{2}{\sqrt{5}}\approx 0.9$ s, not 1 s. Option C.