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PhysicsKinematics1-DEasy2 minPYQ_2025

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An object with mass 500 g moves along x -axis with speed $v = 4 x m / s$ . The force acting on the object is :

Answer:

Solution:

$F = M \times a v = 4 x v^{2} = 16 x 2 v \frac{d v}{d x} = 16 \frac{v d v}{d x} = \frac{16}{2} = 8 F = 0.5 \times 8 = 4 N$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: PYQ_2025

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