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PhysicsKinematics1-DEasy2 minPYQ_2024
PhysicsEasynumerical

A particle initially at rest starts moving from reference pointx=0alongx-axis, with velocityvthat varies asv=4x m s-1. The acceleration of the particle is _____m s-2.

Answer:
8.00
Solution:

Given: v=4x

Instantaneous acceleration of the particle can be written as, a=vdvdx

=4x×4×12x-1/2=8 m s-2

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D
2mℹ️ Source: PYQ_2024

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