A body is thrown with a velocity of 9.8 ms making an angle of 3 0 ∘ with the horizontal. It will hit the ground after a time

Time of flight = g 2 u s i n θ = 9.8 2 × 9.8 × s i n 3 0 ∘ = 2 × 2 1 = 1 sec

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PhysicsKinematics2-D & 3DEasy2 minPYQ_2024

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A body is thrown with a velocity of 9.8 ms making an angle of $3 0^{\circ}$ with the horizontal. It will hit the ground after a time

Answer:

Solution:

Time of flight $= \frac{2 u s i n θ}{g}$ $= \frac{2 \times 9.8 \times s i n 3 0 ^{\circ}}{9.8} = 2 \times \frac{1}{2} = 1 sec$

Stream:BITSATSubject:PhysicsTopic:KinematicsSubtopic:2-D & 3D

⏱ 2mℹ️ Source: PYQ_2024

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