Two projectiles are projected at 30 ° and 60 ° with the horizontal with the same speed. The ratio of the maximum height attained by the two projectiles respectively is:

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The maximum height is given by, H = u 2 sin 2 θ 2 g . The given data is θ 1 = 30 ° θ 2 = 60 ° u 1 = u 2 Therefore, H 1 max H 2 max = u 1 2 sin 2 θ 1 u 2 2 sin 2 θ 2 = sin 30 ° sin 60 ° 2 = 1 2 3 2 2 = 1 3

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