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PhysicsKinematics2-D & 3DEasy2 minPYQ_2022
PhysicsEasynumerical

An object is projected in the air with initial velocityuat an angleθ. The projectile motion is such that the horizontal rangeR, is maximum. Another object is projected in the air with a horizontal range half of the range of first object. The initial velocity remains same in both the case. The value of the angle of projection, at which the second object is projected, will be _____  degree.

Answer:
15.00
Solution:

The maximum range is given by, Rmax=u2sin245°g=u2 g.

For the range to be half of the maximum range,

Rmax2=u22 g=u2sin2θg

sin2θ=12

2θ=30°or 2θ=150°

θ=15°,75°

Therefore, answer is 15 or 75

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:2-D & 3D
2mℹ️ Source: PYQ_2022

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