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Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DMedium2 minPYQ_2021

PhysicsMediumsingle choice

A scooter accelerates from rest for time $t_{1}$ at constant rate $a_{1}$ and then retards at constant rate $a_{2}$ for time $t_{2}$ and comes to rest. The correct value of $\frac{t_{1}}{t_{2}}$ will be :

Question diagram: A scooter accelerates from rest for time t 1 at constant rat

Options:

Answer:

A

Solution:

Draw $v t$ curve

$\tan θ_{1} = a_{1} = \frac{v_{\max}}{t_{1}}$
$& \tan θ_{2} = a_{2} = \frac{v_{\max}}{t_{2}}$
$\div$ above

$\frac{t_{1}}{t_{2}} = \frac{a_{2}}{a_{1}}$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: PYQ_2021

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