Physics - Kinematics Question with Solution | TestHub

PhysicsKinematicsRelativeMedium2 minPYQ_2021

PhysicsMediumsingle choice

A butterfly is flying with a velocity $4 \sqrt{2} m s^{- 1}$ in north-east direction. Wind is slowly blowing at $1 m s^{- 1}$ from north to south. The resultant displacement of the butterfly in $3$ seconds is:

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Answer:

Solution:

${\vec{V}}_{BW} = 4 \sqrt{2} \cos 4 5 \hat{i} + 4 \sqrt{2} \sin 4 5 \hat{j}$
$= 4 \hat{i} + 4 \hat{j}$
${\vec{V}}_{w} = - \hat{j}$
${\vec{V}}_{B} = {\vec{V}}_{BW} + {\vec{V}}_{w} = 4 \hat{i} + 3 \hat{j}$
${\vec{S}}_{B} = {\vec{V}}_{B} \times t = (4 \hat{i} + 3 \hat{j}) \times 3 = 12 \hat{i} + 9 \hat{j}$
$|{\vec{S}}_{B}| = \sqrt{(12)^{2} + (9)^{2}} = 15 m$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:Relative

⏱ 2mℹ️ Source: PYQ_2021

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