A cyclist is moving with a constant acceleration of 1 . 2 m s - 2 on a straight track. A racer is moving on a circular path of the radius 150 m at a constant speed of 15 m s - 1 . Find the magnitude o

Question

A cyclist is moving with a constant acceleration of $1.2 m s^{- 2}$ on a straight track. A racer is moving on a circular path of the radius $150 m$ at a constant speed of $15 m s^{- 1}$ . Find the magnitude of the velocity of racer which is measured by the cyclist has reached a speed of $20 m s^{- 1}$ for the position represented in the figure.

TestHub · Accepted Answer

Let v → c = actual velocity of cyclist along x - a x i s v → r = the velocity of racer along tangent of circular path (shown in figure) ∴ v → r c = v → r - v → c Hence v → c = 20 i ^ v → r c = V r cos ⁡ 30 o j ^ + V r sin ⁡ 30 o i ^ Or v → r = 15 cos ⁡ 30 j ^ + 15 sin ⁡ 30 i ^ = 15 2 2 j ^ + 15 2 i ^ ∴ v → r c = v → r - v → c = 15 3 2 j ^ + 15 3 2 j ^ = - 12.5 i ^ + 15 3 2 j ^ ∴ v → r c = - 12.5 2 + 15 3 2 2 = 18 .03 m s - 1

Physics - Kinematics Question with Solution | TestHub

Options:

Doubts & Discussion