Physics - Kinematics Question with Solution | TestHub

Initial velocities of the particle

${\text{u}}_{\text{x}}=10\cos 53=6\mathrm{ m/s}$

${\text{u}}_{\text{y}}=10\sin 53=8\mathrm{ m/s}$

$6\mathrm{t}=1+\mathrm{t}+\mathrm{x}.\frac{3}{5}$[where x is the length of the hypotenuse of the wedge]

$5\mathrm{t}=1+\frac{3\mathrm{x}}{5}$(in$\text{x}$- direction)

$8\mathrm{t}-5{\mathrm{t}}^2=4.\frac{\mathrm{x}}{5}$(in$\text{y}$- direction)

$\mathrm{x}=\frac{35}{9}\mathrm{m}$

Height$=\frac{35}{9}\times \frac{4}{5}=\frac{28}{9}\mathrm{m}$