Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DEasy2 minPYQ_2020

PhysicsEasysingle choice

A body starts from rest and is uniformly accelerated for $30 s$ . The distance travelled in the first $10 s$ is $S_{1}$ , next $10 s$ is $S_{2}$ and the last 10 s is $S_{3}$ . Then $S_{1} : S_{2} : S_{3}$ is the same as

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Answer:

Solution:

a = constant

$S_{1} = v_{0} t + \frac{1}{2} a t^{2}$

$v_{1} = v_{0} + a t$

$S_{2} = v_{1} t + \frac{1}{2} {at}^{2}$ $\Rightarrow v_{0} t + \frac{3}{2} a t^{2}$

$v_{2} = v_{1} + at$

$= v_{0} + 2 at$

$S_{3} = v_{2} t + \frac{1}{2} {at}^{2}$

$= v_{0} t + \frac{5}{2} {at}^{2}$

$v_{0} = 0$

$S_{1} = \frac{1}{2} {at}^{2}$ ; $S_{2} = \frac{3}{2} {at}^{2}$ ; $S_{3} = \frac{5}{2} {at}^{2}$

$S_{1} : S_{2} : S_{3} = 1 : 3 : 5$

Stream:NTA_ABHYASSubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: PYQ_2020

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Physics - Kinematics Question with Solution | TestHub

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