Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics2-D & 3DEasy2 minPYQ_2020

PhysicsEasysingle choice

A ball is projected at an angle of $30 °$ above with the horizontal from the top of a tower and strikes the ground in $5 s$ at an angle of $45 °$ with the horizontal. Find the speed with which it was projected.

Options:

Answer:

Solution:

$v_{x} = - v_{y}$

$u \cos 30 ° = - (u \sin 30 ° - g t)$

$u \frac{\sqrt{3}}{2} = - (\frac{u}{2} - 10 \times 5)$

$u (\frac{\sqrt{3} + 1}{2}) = 50$

$\Rightarrow u = 100 (\frac{1}{\sqrt{3} + 1}) \Rightarrow u = 50 (\sqrt{3} - 1) {m s}^{- 1}$

Subject:PhysicsTopic:KinematicsSubtopic:2-D & 3D

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...