Physics - Kinematics Question with Solution | TestHub

$\text{T}=\frac{{\text{2u sin 90}}^{\text{o}}}{{\text{g cos 30}}^o}=\frac{2\text{u}}{\text{g}\text{cos}30^{\text{o}}}$

$\text{R}=\frac{1}{2}\times \left({\text{g sin 30}}^{\text{o}}\right)\times \frac{4{\text{u}}^2}{{\text{g}}^2{\text{cos}}^2{30}^{\text{o}}}$

$\text{R}=\frac{2{\text{u}}^2\times 4}{2\times 10\times 3}=\frac{2\times 10\times 10\times 4}{2\times 10\times 3}=\frac{40}{3}m$