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Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics2-D & 3DMedium2 minPYQ_2020
PhysicsMediummultiple choice

Starting at timet=0from the origin with speed1 m s-1, a particle follows a two-dimensional trajectory in thex-yplane so that its coordinates are related by the equationy=x22. Thexandycomponents of its acceleration are denoted byaxanday, respectively. Then

Question diagram: Starting at time t = 0 from the origin with speed 1 m s - 1

Options:(select one or more)

Answer:
A, B, C, D
Solution:

y=x22

dydt=12×2xdxdt

vy=xvx

dvydt=dxdt×dxdt+xd2vxdt2

ay=vx2+xax

If x=0, ay=vx2=1, No matters what is the value of ax hence, Option A is correct.

If ax=0 then x=vxt=t

at t=1; x=1 m

then angle made by velocity vector with x -axis

tanθ=vyvx=x=1θ=45°

Stream:JEE_ADVSubject:PhysicsTopic:KinematicsSubtopic:2-D & 3D
2mℹ️ Source: PYQ_2020

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