Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DEasy2 minPYQ_2020

PhysicsEasysingle choice

Displacement $x$ versus $t^{2}$ graph is shown for a particle. The acceleration of the particle is

Options:

Answer:

Solution:

From the graph,

$x = S l o p e (t^{2})$

$x = \frac{2 - 0}{1 - 0} (t^{2})$

$x = 2 t^{2}$

$\frac{d x}{d t} = 4 t$

$\frac{d^{2} x}{d t^{2}} = 4$

$a = 4 m s^{- 2}$ $[∵ \frac{d^{2} x}{d t^{2}} = a]$

Stream:NTA_ABHYASSubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: PYQ_2020

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