From the top of a 64 metres high tower, a stone is thrown upwards vertically with the velocity of 48 m / s . The greatest height (in metres) attained by the stone, assuming the value of the gravitatio

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From the top of a 64 metres high tower, a stone is thrown upwards vertically with the velocity of 48 m / s . The greatest height (in metres) attained by the stone, assuming the value of the gravitational acceleration g = 32 m / s 2 , is:

TestHub · Accepted Answer

We know that v 2 = u 2 + 2 g s . At greatest height v = 0 u = 48 m / sec g = - 32 m / sec 2 S = 48 × 48 2.32 = 36 m Total distance = 64 m + 36 m = 100 m = 100 m

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