Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics1-DMedium2 minPYQ_2007

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The velocity of a particle is $v = v_{0} + gt + ft^{2}$ . If its position is $x = 0$ at $t = 0$ , then its displacement after unit time $(t = 1)$ is

Answer:

Solution:

$\int_{0}^{x} dx = \int_{0}^{1} (V_{0} + gt + ft^{2}) dt$ $x = v_{0} + g (\frac{1}{2}) + f (\frac{1}{3})$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:1-D

⏱ 2mℹ️ Source: PYQ_2007

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