Start Free Mock LoginAlready registered? Login here

Physics - Kinematics Question with Solution | TestHub

PhysicsKinematics2-D & 3DEasy2 minPDF

PhysicsEasynumerical

A ball is projected upward with velocity 20m/s from a van moving with constant velocity of 20 m/s in horizontal direction. What is the ratio of range to the maximum height achieved by the ball for an observer on ground? $(g = 10 m / s^{2})$

Answer:

4.00

Solution:

In the ground frame, horizontal velocity is 20 m/s and vertical launch velocity is 20 m/s.

$R = \frac{u _{x} ( 2 u _{y} )}{g} = 80 m$

$H = \frac{u _{y}^{2}}{2 g} = 20 m$

$R / H = 4$

Stream:JEESubject:PhysicsTopic:KinematicsSubtopic:2-D & 3D

⏱ 2mℹ️ Source: PDF

Doubts & Discussion

Loading discussions...