Physics - Kinematics Question with Solution | TestHub

Given initial velocity $u=0$ (starts from rest), distance $S=100\text{ m}$, and time $t=10\text{ s}$. Using the equation of motion$S=ut+\frac{1}{2}a{t}^2$:$$100=(0)(10)+\frac{1}{2}a(10{)}^2$$ $$100=0+\frac{1}{2}a(100)$$ $$100=50a⟹a=\frac{100}{50}=2{\text{ m/s}}^2$$