A body heated up to t 1 = 10 0 ∘ C was lowered into the vessel with water. The water temperature rose from t 2 = 2 0 ∘ C up to t 3 = 3 0 ∘ C . What will be the temperature of the water if anothe

Question

A body heated up to t 1 ​ = 10 0 ∘ C was lowered into the vessel with water. The water temperature rose from t 2 ​ = 2 0 ∘ C up to t 3 ​ = 3 0 ∘ C . What will be the temperature of the water if another identical body, heated to t 4 ​ = 8 0 ∘ C is also dipped in it after that? The heat capacity of the vessel and heat losses negligible.

TestHub · Accepted Answer

Let the body have heat capacity m S 1 ​ and the water M S 2 ​ . First dip: m S 1 ​ ( 100 − 30 ) = M S 2 ​ ( 30 − 20 ) 7 m S 1 ​ = M S 2 ​ Second body at 8 0 ∘ C goes into water and first body at 3 0 ∘ C . Final temperature T : m S 1 ​ ( 80 − T ) = ( M S 2 ​ + m S 1 ​ ) ( T − 30 ) 80 − T = 8 ( T − 30 ) 9 T = 320 T = 9 320 ​ ∘ C

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