Two moles of a monoatomic ideal gas is taken from A to C through path ABC. If temperature at A is $T_{0}$ , then for process ABC :
Statement-I : Change in internal energy of the gas is $24 RT_{0}$ .
Statement-II : Heat absorbed by the gas is $10 RT_{0}$ .

Question

Two moles of a monoatomic ideal gas is taken from A to C through path ABC. If temperature at A is $T_{0}$ , then for process ABC :

Statement-I : Change in internal energy of the gas is $24 RT_{0}$ .

Statement-II : Heat absorbed by the gas is $10 RT_{0}$ .

TestHub · Accepted Answer

W = W AB ​ + W BC ​ = Area under curve = P 0 ​ ( 2 V 0 ​ ) = 2 P 0 ​ V 0 ​ = 4 RT 0 ​ T ∝ PV ⇒ T C ​ T A ​ ​ = ( 3 P 0 ​ ) ( 3 V 0 ​ ) P 0 ​ V 0 ​ ​ = 9 1 ​ ⇒ T C ​ = 9 T 0 ​ Δ U = nC V ​ ( T C ​ − T A ​ ) = 2 × 2 3 R ​ ( 9 T 0 ​ − T 0 ​ ) = 24 RT 0 ​ (Statement-I true) ( Δ Q ) ABC ​ = ( Δ W ) ABC ​ + ( Δ U ) ABC ​ = 4 RT 0 ​ + 24 RT 0 ​ = 28 RT 0 ​  = 10 RT 0 ​ (Statement-II false) hence (B).

Physics - Heat & Thermo Question with Solution | TestHub

Options:

Doubts & Discussion