In insulated container, there are two fluid with specific heat capacities c 1 and c 2 , separated by insulating barrier. Liquid temperatures are different. The partition is removed, and after the

Question

In insulated container, there are two fluid with specific heat capacities c 1 ​ and c 2 ​ , separated by insulating barrier. Liquid temperatures are different. The partition is removed, and after the establishment of thermal equilibrium the difference between the initial temperature of first liquid and temperature established in the vessel is two times smaller than the difference between the initial temperature of liquids. Find the mass ratio of the first and second fluid

TestHub · Accepted Answer

Heat lost by the first = heat gained by the second:
$m_{1} c_{1} (T_{1} - T) = m_{2} c_{2} (T - T_{2})$
Given:
$T_{1} - T = \frac{T _{1} - T _{2}}{2}$
$m_{1} c_{1} \frac{T _{1} - T _{2}}{2} = m_{2} c_{2} \frac{T _{1} - T _{2}}{2}$
$\frac{m _{1}}{m _{2}} = \frac{c _{2}}{c _{1}}$

Physics - Heat & Thermo Question with Solution | TestHub

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