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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoCalorimetryMedium2 minQB

PhysicsMediumsingle choice

Steam is passed into $22 gm$ of water at $20^{\circ} C$ . The mass of water that will be present when the water acquires a temperature of $90^{\circ} C$ (Latent heat of steam is $540 cal/gm$ ) is :

Options:

Answer:

Solution:

Steam condenses, then cools.
$q = 540 + (100 - 90)$
$q = 550 cal/g$
$Q = 22 (90 - 20)$
$Q = 1540 cal$
$550 m = 1540$
$m = 2.8 g$
$m_{total} = 24.8 g$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Calorimetry

⏱ 2mℹ️ Source: QB

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