Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoRadiationMedium2 minQB

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Passage / Comprehension

A body cools in surroundings at a constant 30°C. Its heat capacity is 2 J/°C and its initial temperature is 40°C. Assume Newton's law of cooling. It cools to 36°C in 10 minutes.

In further 10 minutes it will cool from 36°C to :

Options:

Answer:

Solution:

Let x be the temperature after the next 10 minutes.
$\frac{40 - 36}{10} = k (38 - 30)$
$\frac{36 - x}{10} = k (\frac{36 + x}{2} - 30)$
$\frac{4}{36 - x} = \frac{8}{x /2 - 12}$
$2 x - 48 = 288 - 8 x \Rightarrow x = 33. 6^{\circ} C$
Answer D.

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Radiation

⏱ 2mℹ️ Source: QB

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