Suppose that thermal energy released by cooling water of volume 1 m 3 by 1 ∘ C is used to raise temperature of air by 1 ∘ C at constant volume. What is volume of air that can be heated by 1 ∘ C : (Given : 1 cal = 4.2 J ; s air = 1 J/gm ∘ C ; s water = 1 cal/gm ∘ C ; ρ air = 1.2 kg / m 3 ; ρ water = 1 gm /cc)

m w = 1 0 6 g Q w = 1 0 6 ( 1 ) ( 1 ) ( 4.2 ) Q w = 4.2 × 1 0 6 J Air mass in volume V : m a = 1200 V g 1200 V = 4.2 × 1 0 6 V = 3500 m 3

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoCalorimetryMedium2 minQB

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Suppose that thermal energy released by cooling water of volume 1 $m^{3}$ by $1^{\circ} C$ is used to raise temperature of air by $1^{\circ} C$ at constant volume. What is volume of air that can be heated by $1^{\circ} C$ : (Given : $1 cal$ = $4.2 J$ ; $s_{air}$ = $1 J/gm$ $^{\circ} C$ ; $s_{water}$ = $1 cal/gm$ $^{\circ} C$ ; $ρ_{air}$ = $1.2 kg$ / $m^{3}$ ; $ρ_{water}$ = $1 gm$ /cc)

Options:

Answer:

Solution:

$m_{w} = 1 0^{6} g$
$Q_{w} = 1 0^{6} (1) (1) (4.2)$
$Q_{w} = 4.2 \times 1 0^{6} J$
Air mass in volume
$V : m_{a} = 1200 V g$
$1200 V = 4.2 \times 1 0^{6}$
$V = 3500 m^{3}$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Calorimetry

⏱ 2mℹ️ Source: QB

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