Physics - Heat & Thermo Question with Solution | TestHub

A steel rod is 4.000 cm in diameter at 30 °C. A brass ring has an interior diameter of 3.992 cm at 30 ${}^{\circ }\mathrm{C}$. In order that the ring just slides onto the steel rod, the common temperature of the two should be nearly $({\alpha }_{\text{steel }}=11\times 10^{-6}/{}^{\circ }\mathrm{C}$ and ${\alpha }_{\text{brass }}=19\times 10^{-6}/{}^{\circ }\mathrm{C})$