A glass bowl of water equivalent of 10 g is at room temperature of 20°C when 40 g water at 100°C is poured in it. Also 5g of ice at 0°C is put in the water. If no heat is lost to the surroundings, the

Question

A glass bowl of water equivalent of 10 g is at room temperature of 20°C when 40 g water at 100°C is poured in it. Also 5g of ice at 0°C is put in the water. If no heat is lost to the surroundings, the final temperature of the mixture is

TestHub · Accepted Answer

Bowl & ice will gain heat ​ 10 × ( T − 20 ) + 5 × 80 + 5 × T = 40 × ( 100 − T ) ⇒ ​ 10 T − 200 + 400 + 5 T = 4000 − 40 T ⇒ ​ 55 T = 3800 ​ T = 11 760 ​ = 6 9 ∘ C ​

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