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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoDifferent processesMedium2 minQB

PhysicsMediuminteger

An ideal gas is heated such that $TV^{3} =$ Constant. Ratio of internal energy change to magnitude of work done if adiabatic exponent of gas is $3/2$ .

Answer:

Solution:

$T V^{3} = const \Rightarrow (\frac{P V}{n R}) V^{3} = const \Rightarrow P V^{4} = const (x = 4)$

$W = \frac{n R Δ T}{1 - x}, Δ U = \frac{n R Δ T}{γ - 1}$

$\frac{Δ U}{∣ W ∣} = \frac{∣1 - x ∣}{γ - 1} = \frac{∣1 - 4∣}{\frac{3}{2} - 1} = \frac{3}{1/2} = 6$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Different processes

⏱ 2mℹ️ Source: QB

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