An aluminium container of mass 100 gm contains 200 gm of ice at − 2 0 ∘ C . Heat is added to the system at the rate of 100 cal /s. The temperature of the system after 4 minutes will be (specific heat

Question

An aluminium container of mass 100 gm contains 200 gm of ice at − 2 0 ∘ C . Heat is added to the system at the rate of 100 cal /s. The temperature of the system after 4 minutes will be (specific heat of ice = 0.5 and L = 80 cal/gm, specific heat of Al = 0.2 cal/gm ∘ C )

TestHub · Accepted Answer

Heat supplied: Q = 100 × 240 = 24000 cal Warming ice and aluminium to freezing: Q 1 ​ = 200 ( 0.5 ) ( 20 ) + 100 ( 0.2 ) ( 20 ) = 2400 cal Melting ice: Q 2 ​ = 200 ( 80 ) = 16000 cal Remaining heat warms water and container: 24000 − 2400 − 16000 = 5600 cal 5600 = ( 200 + 100 × 0.2 ) T T = 5600/220 ≈ 25. 5 ∘ C

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