Start Free Mock LoginAlready registered? Login here

Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoConductionMedium2 minQB

PhysicsMediumsingle choice

Consider a compound slab consisting of two different materials having equal lengths, thicknesses, cross section and thermal conductivities $K$ and $2 K$ respectively, are connected in series. The equivalent thermal conductivity of the slab is

Options:

Answer:

Solution:

For slabs in series,

$K_{eq} = \frac{l _{1} + l _{2}}{\frac{l _{1}}{K _{1}} + \frac{l _{2}}{K _{2}}}$

$K_{eq} = \frac{2 l}{\frac{l}{K} + \frac{l}{2 K}}$

$K_{eq} = \frac{4}{3} K$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Conduction

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...