Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoCyclic processMedium3 minQB

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Passage / Comprehension

Three processes make the thermodynamic cycle in the P-V diagram.
Process 1 to 2 is isothermal; 2 to 3 is isochoric; 3 to 1 is adiabatic.
Net work over the cycle is 10 J. Internal energy decreases by 20 J from 2 to 3. During 3 to 1, 20 J of work is done on the system.

How much heat is added to the system during process $1 \to 2$ is

Options:

Answer:

Solution:

For the full cycle, net work is 10 J.
During 2 to 3, volume is constant, so $W_{23} = 0$ .
During 3 to 1, 20 J of work is done on the gas, so $W_{31} = - 20 J$ .
Thus $W_{12} + 0 - 20 = 10$ , giving $W_{12} = 30 J$ .
Process 1 to 2 is isothermal; $Δ U_{12} = 0$ , hence $Q_{12} = 30 J$ .

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Cyclic process

⏱ 3mℹ️ Source: QB

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