Consider an ideal diatomic gas undergoing a process P T 2 3 = constant. The molar heat capacity for the process (R is universal gas constant) is :

P T 3/2 = constant P × ( n R P V ) 3/2 = constant ⇒ P 2 5 V 2 3 = constant ⇒ P V 5 3 = constant C = C v + 1 − x R for a process P V x = constant ⇒ C = 2 5 R + 1 − 5 3 R = 2 5 R + 2/5 R = 5 R

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Consider an ideal diatomic gas undergoing a process $P T^{\frac{3}{2}} =$ constant. The molar heat capacity for the process (R is universal gas constant) is :

Options:

Answer:

Solution:

$P T^{3/2} =$ constant

$P \times (\frac{P V}{n R})^{3/2} = constant \Rightarrow P^{\frac{5}{2}} V^{\frac{3}{2}} = constant \Rightarrow P V^{\frac{3}{5}} = constant C = C_{v} + \frac{R}{1 - x} for a process P V^{x} = constant \Rightarrow C = \frac{5 R}{2} + \frac{R}{1 - \frac{3}{5}} = \frac{5 R}{2} + \frac{R}{2/5} = 5 R$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Different processes

⏱ 2mℹ️ Source: QB

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