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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoKTGEasy2 minQB

PhysicsEasysingle choice

A mixture of 2 moles of helium gas (atomic mass = 4u) $,$ and 1 mole of argon gas (atomic mass = 40 u) is kept at $300 K$ in a container. The ratio of their rms speeds $[\frac{V_{r m s} (h e l i u m)}{V_{r m s} (a r g o n)}],$ is close to:

Options:

Answer:

Solution:

$V_{R M S} = \sqrt{\frac{3 R T}{M}}$

$∴ \frac{{(V_{R M S})}_{H e}}{{(V_{R M S})}_{A r}} = \sqrt{\frac{M_{A r}}{M_{H e}}} = \sqrt{\frac{40}{4}} = \sqrt{10} = 3.16$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: QB

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