A bullet of mass 70 gm travelling at 250 m/s strikes and gets embedded in ice at 0 ∘ C . Assuming that temperature of bullet does not change, find the amount of ice that melts.

The kinetic energy melts the ice. Use: J = 4.2 J/cal L = 80 cal/g 2 1 × 70 × 1 0 − 3 × 25 0 2 = m × L 2187.5 = m × 80 × 4.2 × 1 0 3 m = 768 5 kg

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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoCalorimetryMedium2 minQB

PhysicsMediumsingle choice

A bullet of mass $70 gm$ travelling at 250 m/s strikes and gets embedded in ice at $0^{\circ} C$ . Assuming that temperature of bullet does not change, find the amount of ice that melts.

Options:

Answer:

Solution:

The kinetic energy melts the ice. Use:
$J = 4.2 J/cal$
$L = 80 cal/g$
$\frac{1}{2} \times 70 \times 1 0^{- 3} \times 25 0^{2} = m \times L$
$2187.5 = m \times 80 \times 4.2 \times 1 0^{3}$
$m = \frac{5}{768} kg$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Calorimetry

⏱ 2mℹ️ Source: QB

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