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Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoSecond Law of ThermodynamicsMedium3 minQB

PhysicsMediumsingle choice

Passage / Comprehension

A Carnot refrigerator absorbs heat from water at 0°C and releases it into a room at 27°C.
It turns 1 kg of water at 0°C into ice at 0°C. The latent heat of ice is 80 kcal/kg.
The coefficient of performance is heat taken from the cold body divided by the work input: $β = Q_{c} / W = T_{c} / (T_{h} - T_{c})$ .

What is the coefficient of performance of the machine ?

Options:

Answer:

Solution:

For a Carnot refrigerator, $T_{c} = 273 K$ and $T_{h} = 300 K$ .
Coefficient of performance $β = \frac{T _{c}}{T _{h} - T _{c}} = \frac{273}{27} \approx 10.1$ , option B.

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:Second Law of Thermodynamics

⏱ 3mℹ️ Source: QB

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