Physics - Heat & Thermo Question with Solution | TestHub

Heat taken by ice to melt at $0^{\circ }\mathrm{C}$ is ${\mathrm{Q}}_2=\mathrm{mL}=540\times 80=43200\mathrm{cal}$ Heat given by water to cool upto $0^{\circ }\mathrm{C}$ is ${\mathrm{Q}}_2=\mathrm{ms}\mathbf{\Delta }\mathbf{\theta }=540\times 1\times \ast 80-0)=43200\mathrm{cal}$ Hence heat given by water is just sufficient to melt the whole ice and final temperature of mixture is $0^{\circ }\mathrm{C}$.