In a thermodynamic process, pressure of a fixed mass of gas is changed in such a manner that the gas releases 30 J of heat and 18 J work was done on gas. If initial internal energy of gas was 60 J, an

Question

In a thermodynamic process, pressure of a fixed mass of gas is changed in such a manner that the gas releases 30 J of heat and 18 J work was done on gas. If initial internal energy of gas was 60 J, and final internal energy is $12 x$ J. Find the value of $x$ .

Answer:

4

Solution:

First law:

$Δ U = Q + W_{o n} = - 30 + 18 = - 12 J$

$U_{f} = 60 - 12 = 48 = 12 x \Rightarrow x = 4$

Answer: 4.

TestHub · Accepted Answer

First law: Δ U = Q + W o n ​ = − 30 + 18 = − 12 J U f ​ = 60 − 12 = 48 = 12 x ⇒ x = 4 Answer: 4.

Physics - Heat & Thermo Question with Solution | TestHub

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