Physics - Heat & Thermo Question with Solution | TestHub

PhysicsHeat & ThermoFirst lawMedium2 minQB

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One mole of a diatomic gas undergoes a thermodynamic process, whose process equation is $P \propto V^{2}$ . The molar specific heat of the gas is

Answer:

Solution:

$P V^{- 2} = constant$

For a polytropic process, $C = C_{V} + \frac{R}{1 - N}$ .

$N = - 2, C_{V} = \frac{5 R}{2}$

$C = \frac{5 R}{2} + \frac{R}{3} = \frac{17 R}{6}$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:First law

⏱ 2mℹ️ Source: QB

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