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PhysicsHeat & ThermoKTGMedium2 minPYQ_2024

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Two vessels $A$ and $B$ are of the same size and are at same temperature. $A$ contains $1 g$ of hydrogen and $B$ contains $1 g$ of oxygen. $P_{A}$ and $P_{B}$ are the pressures of the gases in $A$ and $B$ respectively, then $\frac{P_{A}}{P_{B}}$ is :

Options:

Answer:

Solution:

For both the gases, it follows that

$\frac{P_{A} V_{A}}{P_{B} V_{B}} = \frac{n_{A} R T_{A}}{n_{B} R T_{B}} . . . (1)$

Given $V_{A} = V_{B}$ and $T_{A} = T_{B}$ .

Thus, from equation (1), it follows that

$\begin{array}{rcl} \frac{P_{A}}{P_{B}} & = & \frac{n_{A}}{n_{B}} \\ = & \frac{\frac{1}{2}}{\frac{1}{32}} \\ = & 16 \end{array}$

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG

⏱ 2mℹ️ Source: PYQ_2024

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