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PhysicsHeat & ThermoKTGEasy2 minPYQ_2024
PhysicsEasysingle choice

The temperature of a gas having2.0×1025molecules per cubic meter at1.38 atm(Given,k=1.38×10-23J K-1)is :

Options:

Answer:
A
Solution:

From ideal gas equation, PV=nRT

PV=NNART, where N= total number of molecules

P=NVRNATP=NVkT

1.38×1.01×105=2×1025×1.38×10-23×T

1.01×105=2×102×T

T=1.01×1032500 K

Stream:JEESubject:PhysicsTopic:Heat & ThermoSubtopic:KTG
2mℹ️ Source: PYQ_2024

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